Factoring Polynomials

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Factorisation is a process which is necessary to simplify algebraic expressions and is used to solve the higher degree equations. It is the inverse procedure of the multiplication of the polynomials. Once you factorize a polynomial and then divide the polynomial with the same factors, you would get zero as the remainder. Remember that an algebraic expression is said to be in a factored form only when the whole expression is an indicated product. In this article, we will learn about factoring polynomials, the factorisation of polynomial, how to factor polynomials, and some solved examples. Let us first consider the following examples:

For factorisation of polynomials, you must know how to factor out the common factors using the distributing property. The distributive property tells you that a(b+c) = ab + ac.

Consider this Example:

Find the product of 3×2 and 4x + 3. 

To find the product, you need to multiply each term in the binomial by a common factor 3×2. 

3×2(4x+3) = 3×2(4x)+3×2(3)

Since this is a distributive property, the reverse of it is true as well.

3×2(4x)+3×2 = 3×2(4x+3)

If you start with 3×2(4x) + 3×2(3) you can use this property to factor out 3×2 and get 3×2 (4x + 3).

This resulting expression that you got is in the factored form since it is written as the product of two different polynomials, while the original expression is the sum of two terms.

How to Factor Polynomials?

Factoring polynomials can be done with the help of six different methods which are:

1. Greatest Common Factor (GCF)

2. Grouping Method

3. Sum or difference in two cubes

4. Difference in two squares method

5. General trinomials

6. Trinomial method

Let us learn factoring polynomials by using some of these methods which are used for factoring polynomials frequently. 

Factoring Polynomials by Greatest Common Factor (GCF)

As you learned that for factoring polynomials, you need to first find the greatest common factor of the polynomial that is given. And this is the reverse process of the distributive law. Follow these steps for factoring polynomials by the greatest common factor.

1. The first step is finding the GCF of all the terms in the given polynomial.

2. Then express each term as a product of the GCF and the other factor.

3. Lastly, use the distributive property for factoring out the GCF.

Consider the following example.

Factorize 2×3 – 6×2.

The first step is to find the GCF. Doing so, you get,

2×3 = 2 . x . x . x

6×2 = 2 . 3 . x . x

Hence, the GCF of the expression is

2×3 – 6×2 is 2 . x . x = 2×2

The next step is expressing each term as the product of 2×2 and the other factor. Doing so, you get,

2×3 = (2×2)(x)

6×2 = (2×2)(3)

You can then write the polynomial as:

2×3 – 6×2 = (2×2)(x) – (2×2)(3)

Finally, factorize using the GCF using the distributive property.

(2×2)(x) – (2×2)(3) = (2×2)(x-3)

Factoring Polynomials By Grouping

Factoring polynomials by grouping is usually done with polynomials having 4 terms. The idea of this method is pairing the like terms together and then apply the distributive property for factorising them properly. Consider the following example.

Factorise x3 − 3×2 − x + 3.

You have x3 − 3×2 − x + 3.

Taking out the common pairs and factorising them further gives you,

= x2(x – 3) – ( x – 3 )

=(x2 – 1)(x – 3)

= (x – 1)(x + 1)(x – 3)

Factoring Polynomials Using Identities

Factoring polynomials using identities is done by using the algebraic identities. When it comes to factorisation, the commonly used identities are as follows:

[ (a – b)2 = a2 – 2ab + b2 ], [ (a + b)2 = a2 + 2ab + b2 ] and [a2 – b2= (a + b) (a – b)]

Consider this example:

Factorise the term (x2 – 132)

Using the algebraic identity, you can write the above polynomial as

(x+13) (x-13)

Factoring Polynomials By Factor Theorem

Factoring polynomials by factor theorem is done for a polynomial p(x) having a degree greater than or equal to one. For example,

x – a is considered a factor of p(x), if p(a) = 0

Also, if p(a) = 0, then x – a is called a factor of p(x),

wherein a is a real number.

Factoring Polynomials Examples

1. Factorise the Following:

(x + 1 )2 – 9(x – 2)2

Solution

You have 

(x + 1 )2 – 9(x – 2)2

Taking out the common terms and factorising it, you get,

= (x + 1 )2 – 3(x – 2)2

= ((x + 1) – 3(x – 2))((x + 1) + 3(x – 2))

= (x + 1 -3x + 6)(x + 1 +3x – 6)

= (x + 1 – 3x + 6)(x + 1 + 3x – 6)

Simplifying this further, your answer is

= (-2x + 7)(4x – 5)

2. Factorize the Expression  x2  + 5x + 6.

Solution

For this polynomial expression, we will try factorisation by splitting middle term.

When you factorise by splitting the middle term, you find two terms a and b in a way that you get a + b =5 and ab = 6. When you solve this, you get the values of a and b as 3 and 2 respectively.

Hence, you can write this expression as

x + 3x + 2x + 6 

Factorising this you get x (x + 3) + 2 (x + 3) 

= (x + 3)(x + 2)

Therefore, you can say that ( x + 3) and (x + 2) are the two factors of the polynomial  x2  + 5x + 6.

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