Two trains, A and B start from the stations X and Y towards each other. They take 4 hours 48 mins and 3 hours 20 mins to reach Y and X respectively after they meet. If train A is moving at 50 km/hr, then the speed of train B is    

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Two trains, A and B, embark from distant stations X and Y. While A zooms at 50 km/hr, deduce the velocity of train B in this thrilling journey!

Two trains, A and B start from the stations X and Y towards each other. They take 4 hours 48 mins and 3 hours 20 mins to reach Y and X respectively after they meet. If train A is moving at 50 km/hr, then the speed of train B is

The speed of the train B is 72 km/hr.

Here’s how to find the speed of train B:

Step 1: Convert time taken to decimal hours.

  • Train A: 4 hours 48 minutes = 4 + 48/60 hours = 4.8 hours
  • Train B: 3 hours 20 minutes = 3 + 20/60 hours = 3.33 hours

Step 2: Let the distance between X and Y be “d” kilometers.

Step 3: Use the relative speed formula.

When the trains meet, the combined distance covered is equal to the total distance between X and Y. We can express this using the relative speed formula:

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d = (A’s speed + B’s speed) * time spent together

Step 4: Substitute known values and solve for B’s speed.

We know A’s speed is 50 km/hr and time spent together is the time before they meet (which is unknown). Let B’s speed be “x” km/hr.

d = (50 + x) * t

Since we don’t have the value of “t”, we can eliminate it by using another equation.

Step 5: Use the information about the time taken after meeting.

We know the distance covered by each train after meeting and their respective speeds. Use this information to write two more equations:

  • For Train A: d = 50 * 4.8 (distance = speed * time)
  • For Train B: d = x * 3.33

Step 6: Solve the system of equations.

Now we have three independent equations with three unknowns (d, t, and x). Solve this system of equations to find the value of x, which represents the speed of train B.

Here’s one way to solve the system:

  1. From the equation for Train A, d = 240.
  2. Substitute this value of d in the equation for Train B: 240 = x * 3.33
  3. Solve for x: x = 72 km/hr (approximately)

Therefore, the speed of train B is 72 km/hr.

Time, Distance and Speed in Mathematics

The relationship between time, distance, and speed is a fundamental concept in mathematics, with applications in everyday life and various scientific fields. Here’s a breakdown:

Concepts:

  • Speed: Represents how fast an object moves, calculated as distance traveled divided by time taken (Speed = Distance / Time).
  • Distance: Represents the total length or separation between two points.
  • Time: Represents the duration or interval during which something happens.
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Formulas:

The three concepts are interconnected through three basic formulas:

  1. Speed = Distance / Time: This formula helps you find the speed if you know the distance and time.
  2. Distance = Speed x Time: This formula helps you find the distance if you know the speed and time.
  3. Time = Distance / Speed: This formula helps you find the time if you know the distance and speed.

Relationships:

  • Speed and distance have a direct proportional relationship. This means if the speed increases, the distance covered also increases proportionally, and vice versa.
  • Speed and time have an inverse proportional relationship. This means if the speed increases, the time taken to cover a distance decreases, and vice versa.

Applications:

  • Solving real-world problems: These formulas are used in various scenarios, like calculating travel time, average speed, fuel consumption, etc.
  • Physics and engineering: Understanding motion, forces, and acceleration relies heavily on these concepts.
  • Economics and finance: Calculating rates, interest, and project durations use similar principles.

Additional Information:

  • Units of measurement are crucial when using these formulas. Ensure consistent units (e.g., kilometers for distance, hours for time).
  • Conversions between different units (e.g., miles to kilometers, hours to seconds) might be necessary for calculations.
  • More complex scenarios might involve relative speeds, multiple objects, or non-constant speeds, requiring further mathematical tools.

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